| ⇦ | 
| ⇨ |
A total charge of 5µC is distributed uniformly on the surface of the thin walled semispherical cup. If the electric field strength at the centre of the hemisphere is 9×10⁸NC⁻¹, then the radius of the cup is
{1/4πε₀=9×10⁹N-m²C⁻²}
Options
(a) 5mm
(b) 10mm
(c) 5cm
(d) 10cm
Correct Answer:
5mm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The order of distance of an electron revolving in an atom from nucleus is
- The condition for obtaining secondary maxima in the diffraction pattern
- The magnetic susceptibility of a material of a rod is 299. Permeability of vacuum
- An astronomical telescope arranged for normal adjustment has a magnification of 6.
- A particle of mass m is driven by a machine that delivers a constant power k watts
Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The order of distance of an electron revolving in an atom from nucleus is
- The condition for obtaining secondary maxima in the diffraction pattern
- The magnetic susceptibility of a material of a rod is 299. Permeability of vacuum
- An astronomical telescope arranged for normal adjustment has a magnification of 6.
- A particle of mass m is driven by a machine that delivers a constant power k watts
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply