| ⇦ | 
| ⇨ |
A total charge of 5µC is distributed uniformly on the surface of the thin walled semispherical cup. If the electric field strength at the centre of the hemisphere is 9×10⁸NC⁻¹, then the radius of the cup is
{1/4πε₀=9×10⁹N-m²C⁻²}
Options
(a) 5mm
(b) 10mm
(c) 5cm
(d) 10cm
Correct Answer:
5mm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A uniform force of (3i + j) newton acfs on a particle of mass 2kg
- A astronomical telescope has objective and eye-piece of focal lengths
- If the value of potential in an A.C circuit is 10 V, the peak value of potential is
- A wire carrying current I has the shape as shown in adjoining figure. Linear parts
- A sphere of 4cm radius is suspended with in a hollow sphere of 6cm radius. If the inner
Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A uniform force of (3i + j) newton acfs on a particle of mass 2kg
- A astronomical telescope has objective and eye-piece of focal lengths
- If the value of potential in an A.C circuit is 10 V, the peak value of potential is
- A wire carrying current I has the shape as shown in adjoining figure. Linear parts
- A sphere of 4cm radius is suspended with in a hollow sphere of 6cm radius. If the inner
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply