| ⇦ |
| ⇨ |
A total charge of 5µC is distributed uniformly on the surface of the thin walled semispherical cup. If the electric field strength at the centre of the hemisphere is 9×10⁸NC⁻¹, then the radius of the cup is
{1/4πε₀=9×10⁹N-m²C⁻²}
Options
(a) 5mm
(b) 10mm
(c) 5cm
(d) 10cm
Correct Answer:
5mm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A ball is dropped from a high rise platform at t = 0 starting from rest
- One solid sphere A and another hollow sphere B are of same mass and same outer radii.
- The ratio of magnetic dipole moment of an electron of charge e and mass m
- Two points are located at a distance of 10 m and 15 m from the source of oscillation
- If a magnetic substance is kept in a magnetic field, then which of the following
Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A ball is dropped from a high rise platform at t = 0 starting from rest
- One solid sphere A and another hollow sphere B are of same mass and same outer radii.
- The ratio of magnetic dipole moment of an electron of charge e and mass m
- Two points are located at a distance of 10 m and 15 m from the source of oscillation
- If a magnetic substance is kept in a magnetic field, then which of the following
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply