| ⇦ |
| ⇨ |
A total charge of 5µC is distributed uniformly on the surface of the thin walled semispherical cup. If the electric field strength at the centre of the hemisphere is 9×10⁸NC⁻¹, then the radius of the cup is
{1/4πε₀=9×10⁹N-m²C⁻²}
Options
(a) 5mm
(b) 10mm
(c) 5cm
(d) 10cm
Correct Answer:
5mm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A particle is dropped vertically from rest, from a height.The time taken by it to fall
- The speed of an electron having a wavelength of 10⁻¹⁰ m is
- The electromagnetic theory of light failed to explain
- If an electron and a positron annihilate, the energy released is
- Radius of first orbit of the electron in a hydrogen atom is 0.53 Å. So the radius
Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A particle is dropped vertically from rest, from a height.The time taken by it to fall
- The speed of an electron having a wavelength of 10⁻¹⁰ m is
- The electromagnetic theory of light failed to explain
- If an electron and a positron annihilate, the energy released is
- Radius of first orbit of the electron in a hydrogen atom is 0.53 Å. So the radius
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply