A thin semicircular conducting ring (PQR) of radius r is falling with its plane

⇦

⇨

A thin semicircular conducting ring (PQR) of radius r is falling with its plane vertical in a horizontal magnetic field B, as shown in the figure. The potential difference developed across the ring when its speed is v, is

Options

(a) zero
(b) Bvπr²/2 and P is at higher potential
(c) πrBv and R is at higher potential
(d) 2rBv and R is at higher potential

Correct Answer:

2rBv and R is at higher potential

Explanation:

No explanation available. Be the first to write the explanation for this question by commenting below.

Related Questions:

1. A carnot’s engine operates with source at 127° C and sink at 27°C
2. The diameter of the eye ball of a normal eye is about 2.5 cm. The power of the eye
3. The work done in which of the following processes is equal to the change in internal energy
4. The drift velocity does not depend upon
5. Velocities of sound measured in hydrogen and oxygen gas at a given temperature

Topics: Electromagnetic Induction (76)
Subject: Physics (2479)

---

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

---

Share this page with your friends