| ⇦ | 
| ⇨ |
A spherical planet has a mass Mp and diameter Dp. A particle of mass m falling freely near the surface of this planet will experience an acceleration due to gravity, equal to
Options
(a) 4GMp / dp²
(b) GMpm / dp²
(c) GMp / dp²
(d) 4GMpm / dp²
Correct Answer:
4GMp / dp²
Explanation:
Gravitational attraction force on a parcticle B,
Fᵥ = GMₚm / (Dₚ / 2)²
Acceleration of particle due to gravity
a = Fᵥ / m = 4GMₚ / D²ₚ
Related Questions: - A coil has an area of 0.05 m² and it has 800 turns. It is placed perpendicularly
- If a nucleus ᴢXᴬ emits 9α and 5β-particles, then the ratio of total protons and neutrons
- If the rise in height of capillary of two tubes is 6.6 cm and 2.2 cm
- Ohm’s law is not applicable except to
- The average power dissipated in AC circuit is 2 W. If a current flowing through
Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A coil has an area of 0.05 m² and it has 800 turns. It is placed perpendicularly
- If a nucleus ᴢXᴬ emits 9α and 5β-particles, then the ratio of total protons and neutrons
- If the rise in height of capillary of two tubes is 6.6 cm and 2.2 cm
- Ohm’s law is not applicable except to
- The average power dissipated in AC circuit is 2 W. If a current flowing through
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply