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A spherical planet has a mass Mp and diameter Dp. A particle of mass m falling freely near the surface of this planet will experience an acceleration due to gravity, equal to
Options
(a) 4GMp / dp²
(b) GMpm / dp²
(c) GMp / dp²
(d) 4GMpm / dp²
Correct Answer:
4GMp / dp²
Explanation:
Gravitational attraction force on a parcticle B,
Fᵥ = GMₚm / (Dₚ / 2)²
Acceleration of particle due to gravity
a = Fᵥ / m = 4GMₚ / D²ₚ
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Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A body is thrown vertically up with a velocity u.It passes three points A,B and C
- Reactance of a capacitor of capacitance C µF for A.C freqency (400 / π) Hz is 25 ohm
- The amount of heat energy required to raise the temperature of 1 g of Helium
- A cylindrical tank is filled with water to a level of 3m. A hole is opened at a height
- A particle moves along a circle of radius 20/π m with constant tangential acceleration
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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