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A spherical planet has a mass Mp and diameter Dp. A particle of mass m falling freely near the surface of this planet will experience an acceleration due to gravity, equal to
Options
(a) 4GMp / dp²
(b) GMpm / dp²
(c) GMp / dp²
(d) 4GMpm / dp²
Correct Answer:
4GMp / dp²
Explanation:
Gravitational attraction force on a parcticle B,
Fᵥ = GMₚm / (Dₚ / 2)²
Acceleration of particle due to gravity
a = Fᵥ / m = 4GMₚ / D²ₚ
Related Questions: - The charge flowing through a resistance R varies with time t as Q=at-bt²,
- Two springs with spring constants K₁=1500 N/m and K₂=3000 N/m
- The motion of a particle along a straight line is described by equation
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Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The charge flowing through a resistance R varies with time t as Q=at-bt²,
- Two springs with spring constants K₁=1500 N/m and K₂=3000 N/m
- The motion of a particle along a straight line is described by equation
- An electron of mass Mₑ, initially at rest, moves through a certain distance in a uniform
- The depth at which the effective value of acceleration due to gravity is g/4
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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