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A spherical planet has a mass Mp and diameter Dp. A particle of mass m falling freely near the surface of this planet will experience an acceleration due to gravity, equal to
Options
(a) 4GMp / dp²
(b) GMpm / dp²
(c) GMp / dp²
(d) 4GMpm / dp²
Correct Answer:
4GMp / dp²
Explanation:
Gravitational attraction force on a parcticle B,
Fᵥ = GMₚm / (Dₚ / 2)²
Acceleration of particle due to gravity
a = Fᵥ / m = 4GMₚ / D²ₚ
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Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The nuclear radius of a certain nucleus is 7.2 fm and it has a charge of 1.28×10⁻¹⁷ C.
- Young’s modulus of perfectly rigid body material is
- An artificial satellite is revolving round the earth in a circular orbit. Its velocity
- When a sound wave of wavelength λ is propagating in a medium,
- The half life of a radioactive isotope ‘X’ is 20 years. It decays to another element Y
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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