| ⇦ |
| ⇨ |
A sound absorber attenuates the sound level by 20 dB. The intensity decreases by a factor of
Options
(a) 100
(b) 1000
(c) 10000
(d) 10
Correct Answer:
100
Explanation:
L₁ = 10 log (I₁ / I₀) ; L₂ = 10 log (I₂ / I₀)
L₁ – L₂ = 10 log (I₁ / I₀) – 10 log (I₂ / I₀)
Δ L = 10 log (I₁ / I₂)
20 dB = 10 log (I₁ / I₂)
10 ² = (I₁ / I₂)
I₂ = I₁ / 100.
Related Questions: - If two bodies are projected at 30⁰ and 60⁰ respectively with the same velocity, then
- A block of mass m1 rests on a horizontal table. A light string connected
- An alternating voltage of 220 V, 50 Hz frequency is applied across a capacitor
- Four cells, each of emf E and internal resistance r, are connected in series across
- A block of mass m moving at a velocity v collides with another block of mass 2m
Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If two bodies are projected at 30⁰ and 60⁰ respectively with the same velocity, then
- A block of mass m1 rests on a horizontal table. A light string connected
- An alternating voltage of 220 V, 50 Hz frequency is applied across a capacitor
- Four cells, each of emf E and internal resistance r, are connected in series across
- A block of mass m moving at a velocity v collides with another block of mass 2m
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply