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A sound absorber attenuates the sound level by 20 dB. The intensity decreases by a factor of
Options
(a) 100
(b) 1000
(c) 10000
(d) 10
Correct Answer:
100
Explanation:
L₁ = 10 log (I₁ / I₀) ; L₂ = 10 log (I₂ / I₀)
L₁ – L₂ = 10 log (I₁ / I₀) – 10 log (I₂ / I₀)
Δ L = 10 log (I₁ / I₂)
20 dB = 10 log (I₁ / I₂)
10 ² = (I₁ / I₂)
I₂ = I₁ / 100.
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Topics: Waves
(80)
Subject: Physics
(2479)
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