| ⇦ | 
| ⇨ |
A simple pendulum is suspended from the ceiling of a lift. When the lift is at rest its time period is T. With what acceleration should the lift be accelerated upwards in order to reduce its period to T/2? (g is the acceleration due to gravity)
Options
(a) 4g
(b) g
(c) 2g
(d) 3g
Correct Answer:
3g
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The decay constant of a radio isotope is λ. If A₁ and A₂ are its activities at time
- Before using the tangent galvanometer, its coil is set in
- Heat produced in a resistance according to which law?
- A photocell employs photoelectric effect to convert
- An object is placed 30 cm away from a convex lens of focal length 10 cm and a sharp
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The decay constant of a radio isotope is λ. If A₁ and A₂ are its activities at time
- Before using the tangent galvanometer, its coil is set in
- Heat produced in a resistance according to which law?
- A photocell employs photoelectric effect to convert
- An object is placed 30 cm away from a convex lens of focal length 10 cm and a sharp
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply