⇦ | ⇨ |
A simple pendulum is suspended from the ceiling of a lift. When the lift is at rest its time period is T. With what acceleration should the lift be accelerated upwards in order to reduce its period to T/2? (g is the acceleration due to gravity)
Options
(a) 4g
(b) g
(c) 2g
(d) 3g
Correct Answer:
3g
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - If A.B=A x B,then the angle between A and B is
- The total energy of a simple harmonic oscillator is proportional to
- The work done in which of the following processes is zero?
- A particle is executing the motion x=Acos (ωt-θ). The maximum velocity of the particle is
- A voltmeter of range 2 V and resistance 300Ω cannot be converted into ammeter
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If A.B=A x B,then the angle between A and B is
- The total energy of a simple harmonic oscillator is proportional to
- The work done in which of the following processes is zero?
- A particle is executing the motion x=Acos (ωt-θ). The maximum velocity of the particle is
- A voltmeter of range 2 V and resistance 300Ω cannot be converted into ammeter
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply