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A rod of 10 cm length is moving perpendicular to uniform magntic field of intensity 5×10⁻⁴Wbm⁻². If the acceleration of the rod is 5ms⁻¹, then the rate of increase of induced emf is
Options
(a) 25×10⁻⁴ Vs⁻¹
(b) 2.5×10⁻⁴ Vs⁻¹
(c) 2.0×10⁻⁴ Vs⁻¹
(d) 20×10⁻⁴ Vs⁻¹
Correct Answer:
2.5×10⁻⁴ Vs⁻¹
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A fringe width of a certain interference pattern is β=0.002 cm. What is the distance
- A common emitter amplifier gives an output of 3 V for an input of 0.01 V.
- The unit of surface tension is
- The net electric force on a charge of +3μC at the mid-point on the line joining two
- 1 a.m.u. is equivalent to
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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