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A rod of 10 cm length is moving perpendicular to uniform magntic field of intensity 5×10⁻⁴Wbm⁻². If the acceleration of the rod is 5ms⁻¹, then the rate of increase of induced emf is
Options
(a) 25×10⁻⁴ Vs⁻¹
(b) 2.5×10⁻⁴ Vs⁻¹
(c) 2.0×10⁻⁴ Vs⁻¹
(d) 20×10⁻⁴ Vs⁻¹
Correct Answer:
2.5×10⁻⁴ Vs⁻¹
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In circular coil, when number of turns is doubled and resistance becomes 1/4th
- Light from the constellation Virgo is observed to increase in wavelength by 0.4%
- An aicraft executes a horizontal loop of radius 1 km with a speed of 900 kmh⁻¹
- Two closed organ pipes when sounded simultaneously give 4 beats/second.
- Two coherent monochromatic beams of intensities I and 4I respectively, are superposed.
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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