| ⇦ | 
| ⇨ |
A rod of 10 cm length is moving perpendicular to uniform magntic field of intensity 5×10⁻⁴Wbm⁻². If the acceleration of the rod is 5ms⁻¹, then the rate of increase of induced emf is
Options
(a) 25×10⁻⁴ Vs⁻¹
(b) 2.5×10⁻⁴ Vs⁻¹
(c) 2.0×10⁻⁴ Vs⁻¹
(d) 20×10⁻⁴ Vs⁻¹
Correct Answer:
2.5×10⁻⁴ Vs⁻¹
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The ratio of amplitude of magnetic field to the amplitude of electric field for
- At 0⁰C, 15 gm of ice melts to form water at 0⁰C. The change in entropy is
- A body of mass m is placed on the earth’s surface. It is taken from the earth’s surface
- The current flowing through a lamp marked as 50 W and 250 V is
- The direction of magnetic line of force of a bar magnet is
Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The ratio of amplitude of magnetic field to the amplitude of electric field for
- At 0⁰C, 15 gm of ice melts to form water at 0⁰C. The change in entropy is
- A body of mass m is placed on the earth’s surface. It is taken from the earth’s surface
- The current flowing through a lamp marked as 50 W and 250 V is
- The direction of magnetic line of force of a bar magnet is
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply