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A rod of 10 cm length is moving perpendicular to uniform magntic field of intensity 5×10⁻⁴Wbm⁻². If the acceleration of the rod is 5ms⁻¹, then the rate of increase of induced emf is
Options
(a) 25×10⁻⁴ Vs⁻¹
(b) 2.5×10⁻⁴ Vs⁻¹
(c) 2.0×10⁻⁴ Vs⁻¹
(d) 20×10⁻⁴ Vs⁻¹
Correct Answer:
2.5×10⁻⁴ Vs⁻¹
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two rigid bodies A and B rotate with rotational kinetic energies Eᴀ and Eʙ
- A bar magnet of magnetic moment M is placed at right angles to a magnetic
- A 0.5 kg ball moving with a speed of 12 m/s strikes a hard wall at an angle
- A source of unknown frequency gives 4 beats/s, when sounded with a source harmonic
- A shell of mass 200 g is ejected from a gun of mass 4 kg by an explosion
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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