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A radioactive nucleus of mass M emits a photon of frequency v and the nucleus recoils. The recoil energy will be
Options
(a) Mc² – hv
(b) h²v² / 2Mc²
(c) zero
(d) hv
Correct Answer:
h²v² / 2Mc²
Explanation:
Momentum Mu = E/c = hv / c
Recoil energy
1/2 Mu² = 1/2 . M²u² / M = 1/2M (hv/c)²
= h²v² / 2Mc²
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Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A astronomical telescope has objective and eye-piece of focal lengths
- Which of the following is true for number of spectral lines in going from Lyman series
- There are four light-weight-rod samples A,B,C,D seperately suspended by threads
- Two points are located at a distance of 10 m and 15 m from the source of oscillation
- If a magnet is suspended at an angle 30⁰ to the magnetic meridian, the dip needle
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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