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A radioactive nucleus of mass M emits a photon of frequency v and the nucleus recoils. The recoil energy will be
Options
(a) Mc² – hv
(b) h²v² / 2Mc²
(c) zero
(d) hv
Correct Answer:
h²v² / 2Mc²
Explanation:
Momentum Mu = E/c = hv / c
Recoil energy
1/2 Mu² = 1/2 . M²u² / M = 1/2M (hv/c)²
= h²v² / 2Mc²
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Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- When a charged oil drop moves upwards in an electric field,
- A particle of mass 1mg has the same wavelength as an electron moving with a velocity
- A horizontal straight conductor kept in north-south direction falls under gravity. Then
- A thin rod of length L and mass M is bent at its midpoint into two halves
- If the terminal speed of a sphere of gold (density=19.5 kg/m³) is 0.2 m/s
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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