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A proton is projected with a speed of 3×10⁶ m/s horizontally from east to west. An uniform magnetic field of strength 2×10⁻³ T exist in the vertically upward direction. What would be the acceleration of proton?
Options
(a) 11.6×10¹¹ m/ s²
(b) 17.4×10¹¹ m/ s
(c) 5.8×10¹¹ m/ s²
(d) 2.9×10¹¹ m/ s²
Correct Answer:
5.8×10¹¹ m/ s²
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If ₉₂U²³⁸ undergoes successively 8 ∝-decays and 6 β-decays, the resulting nucleus is
- The binding energy of deutron is 2.2 MeV and that of ₂⁴He is 28 MeV.
- In Young’s double slit experiment the distance between the slits and the screen
- Light of frequency 8×10¹⁵ Hz is incident on a substance of photoelectric work
- A current I ampere flows along the inner conductor of a co-axial cable and returns
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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