⇦ | ⇨ |
A proton is projected with a speed of 3×10⁶ m/s horizontally from east to west. An uniform magnetic field of strength 2×10⁻³ T exist in the vertically upward direction. What would be the acceleration of proton?
Options
(a) 11.6×10¹¹ m/ s²
(b) 17.4×10¹¹ m/ s
(c) 5.8×10¹¹ m/ s²
(d) 2.9×10¹¹ m/ s²
Correct Answer:
5.8×10¹¹ m/ s²
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A hemispherical bowl of radius R is rotating about its axis of symmetry
- 64 drops of mercury, each charged to a potential of 10 V, are combined
- Moderator used in nuclear reactor is
- A ball is dropped into a well in which the water level is at a depth h below the top
- When the wave of hydrogen atom comes from infinity into the first orbit,
Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A hemispherical bowl of radius R is rotating about its axis of symmetry
- 64 drops of mercury, each charged to a potential of 10 V, are combined
- Moderator used in nuclear reactor is
- A ball is dropped into a well in which the water level is at a depth h below the top
- When the wave of hydrogen atom comes from infinity into the first orbit,
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply