| ⇦ |
| ⇨ |
A proton is projected with a speed of 3×10⁶ m/s horizontally from east to west. An uniform magnetic field of strength 2×10⁻³ T exist in the vertically upward direction. What would be the acceleration of proton?
Options
(a) 11.6×10¹¹ m/ s²
(b) 17.4×10¹¹ m/ s
(c) 5.8×10¹¹ m/ s²
(d) 2.9×10¹¹ m/ s²
Correct Answer:
5.8×10¹¹ m/ s²
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - B is doped in Si or Ge, then we will get
- Two parallel beams of positron moving in the same direction will
- A piece of iron is heated in a flame. It first comes dull red then becomes reddish
- Which of the following pairs of quantities does not have same dimensional
- A bar magnet of moment M and pole strength m is cut into parts of equal lengths.
Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- B is doped in Si or Ge, then we will get
- Two parallel beams of positron moving in the same direction will
- A piece of iron is heated in a flame. It first comes dull red then becomes reddish
- Which of the following pairs of quantities does not have same dimensional
- A bar magnet of moment M and pole strength m is cut into parts of equal lengths.
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply