| ⇦ | 
| ⇨ |
A proton beam enters a magnetic field of 10⁻⁴ Wb/m² normally. If the specific charge of the proton is 10¹¹ C/kg and its velocity is 10⁹ m/s, then the radius of the circle described will be
Options
(a) 100 m
(b) 0.1 m
(c) 1 m
(d) 10 m
Correct Answer:
100 m
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions:
- A source and an observer approach each other with same velocity 50 m/s. If the frequency
- In depletion layer of unbiased P-N junction
- The length of second pendulum is 1 m on earth. If mass and diameter
- The rate of increase of thermo-e.m.f. with temperature at the neutral temperature
- The horizontal range and the maximum height of a projectile are equal
Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply