| ⇦ | 
| ⇨ |
A particle of mass m is driven by a machine that delivers a constant power k watts.If the particle starts from rest the force on the particle at time t is
Options
(a) √(mk/2) t⁻¹/²
(b) √(mk) t⁻¹/²
(c) √2mk t⁻¹/²
(d) 1/2√(mk) t⁻¹/²
Correct Answer:
√(mk/2) t⁻¹/²
Explanation:
As we know power P = dw / dt
w = Pt = (1/2) mV²
So, v = √(2Pt / m)
Hence, acceleration a = dV / dt = √(2P / m).(1/2√t)
Therefore, force on the particle time ‘t’ = ma
= √(2Km² / m) . (1/2√t) = √(Km / 2t) = √(mK / 2) t⁻¹/₂
Related Questions:
- X-rays when incident on a metal
- The work function of metals is in the range of 2 eV to 5 eV.
- If r be the distance of a point on the axis of a magnetic dipole from its centre
- Angle of minimum deviation for a prism of reractive index 1.5 equal to the angle
- A disc of moment of inertia (9.8/π²) kg m² is rotating at 600 rpm. If the frequency
Topics: Work Energy and Power
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply