| ⇦ | 
| ⇨ |
A particle moving in a straight line with uniform acceleration is observed to be a distance a from a fixed point initially.It is at distance b,c,d from the same point after n,2n,3n seconds.The acceleration of the particle is
Options
(a) (c-2b+a)/n²
(b) (c+b+a)/9n²
(c) (c+2b+a)/4n²
(d) (c-b+a)/n²
Correct Answer:
(c-2b+a)/n²
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions:
- A particle is moving in a circle with uniform speed v. In moving from a point to another
- The force F acting on a particle of mass m is indicated by the force-time graph
- A charged particle enters a uniform magnetic field with a certain speed at right angles
- A ball is dropped from a height of 20 cm. Ball rebounds to a height of 10cm
- A particle is dropped from a building. It takes 4 sec for the particle to reach the ground
Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply