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A particle moving in a straight line with uniform acceleration is observed to be a distance a from a fixed point initially.It is at distance b,c,d from the same point after n,2n,3n seconds.The acceleration of the particle is
Options
(a) (c-2b+a)/n²
(b) (c+b+a)/9n²
(c) (c+2b+a)/4n²
(d) (c-b+a)/n²
Correct Answer:
(c-2b+a)/n²
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A and B are two vectors and θ is the angle between them ,if |A x B|=√3(A.B),the value of θ
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- The work function of metals is in the range of 2 eV to 5 eV.
- A thin equiconvex lens of refractive index 3/2 and radius of curvature 30 cm
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Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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