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A particle moving in a straight line with uniform acceleration is observed to be a distance a from a fixed point initially.It is at distance b,c,d from the same point after n,2n,3n seconds.The acceleration of the particle is
Options
(a) (c-2b+a)/n²
(b) (c+b+a)/9n²
(c) (c+2b+a)/4n²
(d) (c-b+a)/n²
Correct Answer:
(c-2b+a)/n²
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A particle has initial velocity (3i + 4j) and acceleration (0.1 i+0.3j). It’s speed after 10s
- The velocity of molecules of a gas at temperature 120 K is v. At what temperature
- The electric current in AC circuit is given by the relation i-3 sinωt+4 cos ωt.
- If v is the speed of sound in air, then the shortest length of the closed pipe
- An electric dipole is placed at an angle 30°with an electric field intensity 2×10⁵N/C.
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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