| ⇦ | 
| ⇨ |
A particle moves in a circle of radius 5 cm with constant speed and time period 0.2πs. The acceleration of the particle is
Options
(a) 15 m/s²
(b) 25 m/s²
(c) 36 m/s²
(d) 5 m/s²
Correct Answer:
5 m/s²
Explanation:
Centripetal acceleration aᵥ = 𝜔²r
= ( 2π / T)² r
= (2π / 0.2π)² x 5 x 10⁻²
= 5 m/s²
Related Questions: - A heavy small sized sphere is suspended by a string of length l.The sphere rotates
- The potential energy of a simple harmonic oscillator when the particle is half way
- Photons of energy 6 eV are incident on a metal surface whose work function is 4 eV.
- Which wavelengths of sun is used finally as electric energy?
- The rest mass of a body is m1. It moves with a velocity of 0.6c, then its relativistic
Question Type: Apply
(15)
Difficulty Level: Easy
(1008)
Topics: Motion in Plane
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A heavy small sized sphere is suspended by a string of length l.The sphere rotates
- The potential energy of a simple harmonic oscillator when the particle is half way
- Photons of energy 6 eV are incident on a metal surface whose work function is 4 eV.
- Which wavelengths of sun is used finally as electric energy?
- The rest mass of a body is m1. It moves with a velocity of 0.6c, then its relativistic
Question Type: Apply (15)
Difficulty Level: Easy (1008)
Topics: Motion in Plane (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply