| ⇦ |
| ⇨ |
A particle moves from position r₁ = 3i + 2j -6k to position r₂ = 14i + 13 j+ 9 k under the action of force (4 i + j + 3k)N. The work done will be
Options
(a) 100 J
(b) 50 J
(c) 200 J
(d) 75 J
Correct Answer:
100 J
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - An object of mass 3kg is at rest. Now a force F=6t² i⃗+4t j⃗ is applied on the object
- The intensity at the maximum in a Young’s double slit experiment is I₀.
- In a potentiometer experiment two cells of e.m.f. E₁ and E₂ are used in series
- Angular momentum of the particle rotating with a central force is constant due to
- If an electron and a positron annihilate, the energy released is
Topics: Motion in Plane
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An object of mass 3kg is at rest. Now a force F=6t² i⃗+4t j⃗ is applied on the object
- The intensity at the maximum in a Young’s double slit experiment is I₀.
- In a potentiometer experiment two cells of e.m.f. E₁ and E₂ are used in series
- Angular momentum of the particle rotating with a central force is constant due to
- If an electron and a positron annihilate, the energy released is
Topics: Motion in Plane (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply