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A certain current on passing through a galvanometer produces a deflection of 100 divisions. When a shunt of one ohm is connected, the deflection reduces to division. The galvanometer resistance is
Options
(a) 10 Ω
(b) 9.9 Ω
(c) 100 Ω
(d) 99 Ω
Correct Answer:
99 Ω
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Explanation: Is=I-Ig=100-1=99
G = Is*S/Ig = (99*1)/1 = 99 ohm