| ⇦ | 
| ⇨ |
A certain current on passing through a galvanometer produces a deflection of 100 divisions. When a shunt of one ohm is connected, the deflection reduces to division. The galvanometer resistance is
Options
(a) 10 Ω
(b) 9.9 Ω
(c) 100 Ω
(d) 99 Ω
Correct Answer:
99 Ω
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The work function for metals A,B abd C are respectively 1.92 eV,2.0 eV and 5 eV.
- Two electrons are separated by a distance of 1Å. What is the coulomb force between them?
- Two thin lenses when placed in contact, then the power of combination is +10 D.
- The range of voltmeter is 10V and its internal resistance is 50Ω.
- A 200 W sodium street lamp emits yellow light of wavelength 0.6 µm
Topics: Current Electricity
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The work function for metals A,B abd C are respectively 1.92 eV,2.0 eV and 5 eV.
- Two electrons are separated by a distance of 1Å. What is the coulomb force between them?
- Two thin lenses when placed in contact, then the power of combination is +10 D.
- The range of voltmeter is 10V and its internal resistance is 50Ω.
- A 200 W sodium street lamp emits yellow light of wavelength 0.6 µm
Topics: Current Electricity (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Explanation: Is=I-Ig=100-1=99
G = Is*S/Ig = (99*1)/1 = 99 ohm