| ⇦ |
| ⇨ |
A particle is executing the motion x=Acos (ωt-θ). The maximum velocity of the particle is
Options
(a) Aω cosθ
(b) Aω
(c) Aω sinθ
(d) None of these
Correct Answer:
Aω
Explanation:
x = A cos (ωt – θ)
Velocity = dx/dt = -A sin (ωt – θ)
For maximum value, Since function should be = 1
Maximum velocity = -Aω
Related Questions: - Pure Si at 300 k has equal electrons (nₑ) and hole (nh) concentrations
- If a star converts all helium in its core to oxygen, then energy released per oxygen
- Element ²³⁴U has 92 protons and 234 nucleons in its nucleus. It decays by
- To observed diffraction, the size of the obstacle
- If the binding energy of the nucleon in ₃⁷Li and ₂⁴He nuclei are 5.60 MeV and 7.06 MeV
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Pure Si at 300 k has equal electrons (nₑ) and hole (nh) concentrations
- If a star converts all helium in its core to oxygen, then energy released per oxygen
- Element ²³⁴U has 92 protons and 234 nucleons in its nucleus. It decays by
- To observed diffraction, the size of the obstacle
- If the binding energy of the nucleon in ₃⁷Li and ₂⁴He nuclei are 5.60 MeV and 7.06 MeV
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply