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A particle has initial velocity (2i⃗+3j⃗) and acceleration (0.3i⃗+0.2j⃗). The magnitude of velocity after 10 seconds will be:
Options
(a) 9 √2 units
(b) 5 √2 units
(c) 5 units
(d) 9 units
Correct Answer:
5 √2 units
Explanation:
v⃗ = u⃗ + a⃗t
v = (2i + 3j) + (0.3i + 0.2j) x 10 = 5i +5j
| v⃗ | = √ (5² + 5²)
| v⃗ | = 5 √2
Related Questions: - The momentum of a photon of energy 1 MeV in kg m/s will be
- A particle moves a distance x in time but according to equation x=(t+5)⁻¹
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Difficulty Level: Easy
(1008)
Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The momentum of a photon of energy 1 MeV in kg m/s will be
- A particle moves a distance x in time but according to equation x=(t+5)⁻¹
- The work done in which of the following processes is zero?
- The drive shaft of an automobile rotates at 3600 rpm and transmits 80 HP
- A spherical conductor of radius 2 m is charged to a potential of 120 V. It is now
Difficulty Level: Easy (1008)
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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