| ⇦ | 
| ⇨ |
A particle has initial velocity (2i⃗+3j⃗) and acceleration (0.3i⃗+0.2j⃗). The magnitude of velocity after 10 seconds will be:
Options
(a) 9 √2 units
(b) 5 √2 units
(c) 5 units
(d) 9 units
Correct Answer:
5 √2 units
Explanation:
v⃗ = u⃗ + a⃗t
v = (2i + 3j) + (0.3i + 0.2j) x 10 = 5i +5j
| v⃗ | = √ (5² + 5²)
| v⃗ | = 5 √2
Related Questions: - Thomson coefficient of a conductor is 10 µV/K. Its two ends are kept
- When a ceiling fan is switched off its angular velocity reduces to 50% while
- In Young’s double slit experiment, the fringe width is 1×10⁻⁴ m, if the distance
- The Bohr model of atoms
- A body of mass 1.0 kg is falling with an acceleration of 10 ms⁻².
Difficulty Level: Easy
(1008)
Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Thomson coefficient of a conductor is 10 µV/K. Its two ends are kept
- When a ceiling fan is switched off its angular velocity reduces to 50% while
- In Young’s double slit experiment, the fringe width is 1×10⁻⁴ m, if the distance
- The Bohr model of atoms
- A body of mass 1.0 kg is falling with an acceleration of 10 ms⁻².
Difficulty Level: Easy (1008)
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply