| ⇦ | 
| ⇨ |
Two spheres A and B of masses m1 and m2 respectively collide. A is at rest initially and B is moving with velocity v along x-axis. After collision B has a velocity v/2 in a direction perpendicular to the original direction. The mass A moves after collision in the direction
Options
(a) same as that of B
(b) Opposite to that of B
(c) θ = tan⁻¹ (1/2) to the x-axis
(d) θ = tan⁻¹ ( -1/2) to the x-axis
Correct Answer:
θ = tan⁻¹ (1/2) to the x-axis
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A particle moves with constant speed v along a circular path of radius r and completes
- The potential differences across the resistance, capacitance and inductance
- A light emitting diode(LED) has a voltage drop of 2 volt across it
- The coefficient of performance of a Carnot refrigerator working between 30⁰C and 0⁰C is
- Huygen’s wave theory allows us to know
Topics: Work Energy and Power
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A particle moves with constant speed v along a circular path of radius r and completes
- The potential differences across the resistance, capacitance and inductance
- A light emitting diode(LED) has a voltage drop of 2 volt across it
- The coefficient of performance of a Carnot refrigerator working between 30⁰C and 0⁰C is
- Huygen’s wave theory allows us to know
Topics: Work Energy and Power (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply