A particle free to move along X-axis has potential energy given as U(X) =k(1-e⁻ˣ²)

A Particle Free To Move Along Xaxis Has Potential Energy Physics Question

A particle free to move along X-axis has potential energy given as U(X) =k(1-e-ˣ²),where k is a positive constant of appropriate dimension.Then, for -a

Options

(a) at points away from the origin, the particle is in unstable equilibrium
(b) for any finite non-zero value of x,there is a force directed away from the origin
(c) if its total mechanical energy isk/2, it has its minimum kinetic energy at the origin
(d) if its total mechanical energy isk/2, it has its maximum kinetic energy at the origin

Correct Answer:

if its total mechanical energy isk/2, it has its maximum kinetic energy at the origin

Explanation:

No explanation available. Be the first to write the explanation for this question by commenting below.

Related Questions:

  1. A thin rod of length L and mass M is held vertically with one end on the floor
  2. Two identical charges repel each other with a force equal to 10 mgwt they are 0.6 m
  3. The maximum number of possible interference maxima for slit-seperation equal to
  4. The acceleration due to gravity at a place is π² m/sec². Then the time period
  5. Consider the following two statements about Kirchhoff’s law

Topics: Work Energy and Power (94)
Subject: Physics (2479)

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

NEETLab Mobile App

Share this page with your friends

Be the first to comment

Leave a Reply

Your email address will not be published.


*