| ⇦ |
| ⇨ |
A particle executing simple harmonic motion of amplitude 5 cm has maximum speed of 31.4 cm/s. The frequency of its oscillation is
Options
(a) 4 Hz
(b) 3 Hz
(c) 2 Hz
(d) 1 Hz
Correct Answer:
1 Hz
Explanation:
a = 5 cm, vₘₐₓ = 31.4 cm/s
vₘₐₓ = ωa ⇒ 31.4 = 2πʋ × 5
⇒ 31.4 = 10 × 31.4 × ʋ
⇒ ʋ = 1 Hz
Related Questions: - A short magnet of magnetic moment M, is placed on a straight line. The ratio
- A tuned amplifier circuit is used to generate a carrier frequency of 2 MHz
- The masses of three wires of copper are in the ratio 1:3:5 and lengths
- A silver wire of radius 0.1 cm carries a current of 2A. If the charge density in silver
- In a LCR series circuit, the potential difference between the terminals of the inductor
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A short magnet of magnetic moment M, is placed on a straight line. The ratio
- A tuned amplifier circuit is used to generate a carrier frequency of 2 MHz
- The masses of three wires of copper are in the ratio 1:3:5 and lengths
- A silver wire of radius 0.1 cm carries a current of 2A. If the charge density in silver
- In a LCR series circuit, the potential difference between the terminals of the inductor
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply