| ⇦ | 
| ⇨ |
A particle executing simple harmonic motion of amplitude 5 cm has maximum speed of 31.4 cm/s. The frequency of its oscillation is
Options
(a) 4 Hz
(b) 3 Hz
(c) 2 Hz
(d) 1 Hz
Correct Answer:
1 Hz
Explanation:
a = 5 cm, vₘₐₓ = 31.4 cm/s
vₘₐₓ = ωa ⇒ 31.4 = 2πʋ × 5
⇒ 31.4 = 10 × 31.4 × ʋ
⇒ ʋ = 1 Hz
Related Questions: - When three identical bulbs of 60 W-200 V rating are connected in series to a 200 V
- The internal energy change in a system that has absorbed 2 kcals of heat
- In thermodynamics processes which of the following statements is not true?
- If ∆U and ∆W represent the increase in internal energy and work done by the system
- A wire of length L metre carrying a current I ampere is bent in the form
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- When three identical bulbs of 60 W-200 V rating are connected in series to a 200 V
- The internal energy change in a system that has absorbed 2 kcals of heat
- In thermodynamics processes which of the following statements is not true?
- If ∆U and ∆W represent the increase in internal energy and work done by the system
- A wire of length L metre carrying a current I ampere is bent in the form
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply