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A particle executes simple harmonic oscillations with an amplitude a. The period of oscillation is T. The minimum time taken by the particle to travel half of the amplitude from the equilibrium position is
Options
(a) T/8
(b) T/12
(c) T/2
(d) T/4
Correct Answer:
T/12
Explanation:
Displacement from the mean position y = a sin(2π / T) t
According to the problem y = a/2
a/2 = a sin (2π / T) t
⇒ π / 6 = (2π / T) t ⇒ t = T / 12
This is the minimum time taken by the particle to travel half of the amplitude from the equilibrium position.
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Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The resistance of an ammeter is 13Ω and its scale is graduated for a current
- The temperature of a metal block is increased from 27⁰C to 84⁰C. The rate of radiated energy
- If the lattice parameter for a crystalline structure is 3.6 Å, then the atomic radius
- Newton postulated his corpuscular theory on the basis of
- A small block of super dense material has mass 3 x 10²⁴ kg.It is situated at a height
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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