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A particle executes simple harmonic oscillations with an amplitude a. The period of oscillation is T. The minimum time taken by the particle to travel half of the amplitude from the equilibrium position is
Options
(a) T/8
(b) T/12
(c) T/2
(d) T/4
Correct Answer:
T/12
Explanation:
Displacement from the mean position y = a sin(2π / T) t
According to the problem y = a/2
a/2 = a sin (2π / T) t
⇒ π / 6 = (2π / T) t ⇒ t = T / 12
This is the minimum time taken by the particle to travel half of the amplitude from the equilibrium position.
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Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Initial angular velocity of a circular disc of mass M is ?￢ﾂﾁ.Then, two small spheres
- A ballet dancer, dancing on smooth floor, is spinning about a vertical axis
- A capacitor of 2.5 μF is charged through a resistor of 4 MΩ. In how much time
- Initial pressure and volume of a gas are P and 800cc. If the final volume is 100cc
- A electric dipole is placed at an angle of 30⁰ to a non-uniform electric field.
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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