| ⇦ | 
| ⇨ |
A p-n photodiode is made of a material with a band gap of 2.0 eV. The minimum frequency of the radiation that can be absorbed by the material is nearly
Options
(a) 10 x 10¹⁴ Hz
(b) 5 x 10¹⁴ Hz
(c) 1 x 10¹⁴ Hz
(d) 20 x 10¹⁴ Hz
Correct Answer:
5 x 10¹⁴ Hz
Explanation:
Eₑ = 2.0 eV = 2 x 1.6 x 10⁻¹⁹ J
Eₑ = hv v = Eₑ/h = 2 x 1.6 x 10⁻¹⁹ J / 6.62 x 10⁻³⁴ Js
= 0.4833 x 10¹⁵ s⁻¹ = 4.833 x 10¹⁴ Hz
app. 5 x 10¹⁴ Hz
Related Questions: - The angle between the two vectors A = 3i+4j+5k and B = 3i+4j-5k will be
- Two spheres A and B of masses m and m respectively collide. A is at rest initially
- A layer of colourless oil spreads on water surface. White light is incident on it
- The current in the coil of inductance 5H decreases at the rate of 2 A/s
- A photoelectric surface is illuminated successively by monochromatic light of wavelength
Topics: Electronic Devices
(124)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The angle between the two vectors A = 3i+4j+5k and B = 3i+4j-5k will be
- Two spheres A and B of masses m and m respectively collide. A is at rest initially
- A layer of colourless oil spreads on water surface. White light is incident on it
- The current in the coil of inductance 5H decreases at the rate of 2 A/s
- A photoelectric surface is illuminated successively by monochromatic light of wavelength
Topics: Electronic Devices (124)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply