| ⇦ | 
| ⇨ |
A nucleus ᴢXᴬ emits an α- particle with velocity v. The recoil speed of the daughter nucleus is
Options
(a) A-4/4v
(b) 4v/A-4
(c) v
(d) v/4
Correct Answer:
4v/A-4
Explanation:
According to the question, zXᴬ → z-₂ Yᴬ⁻⁴ + ₂He⁴
Let the recoil speed of daughter nucleus is ʋ’. By the law of conservation of momentum, we have Initial momentum = Final momentum
0 = (A – 4)ʋ’ + 4ʋ
(A – 4) ʋ’ = -4ʋ ⇒ ʋ’ = 4ʋ / (A – 4)
Related Questions: - The ratio of specific charge of an α-particle to that of a proton is
- The horizontal range and the maximum height of a projectile are equal
- The voltage of an a.c.supply varies with time (t) as V=120 sin 100 πt the maximum voltage
- An atom bomb weighing 1 kg explodes releasing 9×10¹³ J of energy.
- A particle moves with constant speed v along a circular path of radius r and completes
Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The ratio of specific charge of an α-particle to that of a proton is
- The horizontal range and the maximum height of a projectile are equal
- The voltage of an a.c.supply varies with time (t) as V=120 sin 100 πt the maximum voltage
- An atom bomb weighing 1 kg explodes releasing 9×10¹³ J of energy.
- A particle moves with constant speed v along a circular path of radius r and completes
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply