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A nucleus ᴢXᴬ emits an α- particle with velocity v. The recoil speed of the daughter nucleus is
Options
(a) A-4/4v
(b) 4v/A-4
(c) v
(d) v/4
Correct Answer:
4v/A-4
Explanation:
According to the question, zXᴬ → z-₂ Yᴬ⁻⁴ + ₂He⁴
Let the recoil speed of daughter nucleus is ʋ’. By the law of conservation of momentum, we have Initial momentum = Final momentum
0 = (A – 4)ʋ’ + 4ʋ
(A – 4) ʋ’ = -4ʋ ⇒ ʋ’ = 4ʋ / (A – 4)
Related Questions: - The mass number of nucleus is always
- A wire carrying current I has the shape as shown in adjoining figure. Linear parts
- A train is moving along a straight path with uniform acceleration
- A thin wire of length L and mass M is bent to form a semicircle.
- If α (current gain) of transistor is 0.98, then what is the value of β
Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The mass number of nucleus is always
- A wire carrying current I has the shape as shown in adjoining figure. Linear parts
- A train is moving along a straight path with uniform acceleration
- A thin wire of length L and mass M is bent to form a semicircle.
- If α (current gain) of transistor is 0.98, then what is the value of β
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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