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A nucleus ᴢXᴬ emits an α- particle with velocity v. The recoil speed of the daughter nucleus is
Options
(a) A-4/4v
(b) 4v/A-4
(c) v
(d) v/4
Correct Answer:
4v/A-4
Explanation:
According to the question, zXᴬ → z-₂ Yᴬ⁻⁴ + ₂He⁴
Let the recoil speed of daughter nucleus is ʋ’. By the law of conservation of momentum, we have Initial momentum = Final momentum
0 = (A – 4)ʋ’ + 4ʋ
(A – 4) ʋ’ = -4ʋ ⇒ ʋ’ = 4ʋ / (A – 4)
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Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- When you move from equator to pole, the value of acceleration due to gravity (g)
- In semiconductor at a room temperature
- 10 mA current can pass through a galvanometer of resistance 25 ohm.
- The height at which the weight of a body becomes 1/16 th, its weight
- A point charge q is situated at a distance r on axis from one end of a thin
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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