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10 mA current can pass through a galvanometer of resistance 25 ohm. What resistance in series should be connected through it, so that it is converted into a voltmeter of 100V?
Options
(a) 0.975 ohm
(b) 99.75 ohm
(c) 975 ohm
(d) 9975 ohm
Correct Answer:
9975 ohm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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V=IR
100=10ma(R+25)
(R+25)=10/10^-3
R+25=10^4
R=9975ohm :ans