| ⇦ | 
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A nucleus ᴢXᴬ emits an α- particle with velocity v. The recoil speed of the daughter nucleus is
Options
(a) A-4/4v
(b) 4v/A-4
(c) v
(d) v/4
Correct Answer:
4v/A-4
Explanation:
According to the question, zXᴬ → z-₂ Yᴬ⁻⁴ + ₂He⁴
Let the recoil speed of daughter nucleus is ʋ’. By the law of conservation of momentum, we have Initial momentum = Final momentum
0 = (A – 4)ʋ’ + 4ʋ
(A – 4) ʋ’ = -4ʋ ⇒ ʋ’ = 4ʋ / (A – 4)
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Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A 50 ohm galvanometer gets full scale deflection when a current of 0.01 A passes
- If a mass of 20g having charge 3.0 mC moving with velocity 20ms⁻¹ enters a region
- A body of mass (4m) is lying in x-y plane at rest. It suddenly explodes into three
- The total kinetic energy of a body of mass 10 kg and radius 0.5 m moving with a velocity
- You are marooned on a frictionless horizontal plane and cannot exert any horizontal
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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