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A motorcycle moving with a velocity 72 kmh⁻¹ on a flat road takes a turn on the road at a point where the radius of curvature of the road is 20 m,the acceleration due to gravity is 10 ms⁻².In order to avoid skidding, he must not bent with respect to the vertical plane by an angle greater than
Options
(a) θ = tan⁻¹(2)
(b) θ = tan⁻¹(6)
(c) θ = tan⁻¹(4)
(d) θ = tan⁻¹(25.92)
Correct Answer:
θ = tan⁻¹(2)
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The radius of a planet is twice the radius of earth. Both have almost
- What is the difference between soft and hard X-ray?
- A ball is moving in a circular path of radius 5 m.If tangential acceleration
- A potentiometer circuit has been set up for finding the internal resistance of a given
- A galvanometer coil has a resistance of 15 ohm and gives full scale deflection
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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