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A force acts on a 3.0 g particle in such a way that the position of the particle as a function of time is given by x = 3t – 4t² + t³ , where x is in metre and t is in second. The work done during the first 4 s is
Options
(a) 570 mj
(b) 450 mj
(c) 490 mj
(d) 530 mj
Correct Answer:
530 mj
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Work Energy and Power
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Subject: Physics
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The wavelength λₑ of an electron and λₚ of a photon are of same energy E are related by
- In n-type semiconductor, electrons are majority charge carriers
- A copper disc of radius 0.1 m is rotated about its centre, with 10 revolutions
- When a biconvex lens of glass having refractive index 1.47 is dipped in a liquid
- The amount of heat energy required to raise the temperature of 1 g of Helium
Topics: Work Energy and Power (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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