| ⇦ | 
| ⇨ |
A force acts on a 3.0 g particle in such a way that the position of the particle as a function of time is given by x = 3t – 4t² + t³ , where x is in metre and t is in second. The work done during the first 4 s is
Options
(a) 570 mj
(b) 450 mj
(c) 490 mj
(d) 530 mj
Correct Answer:
530 mj
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A circular disc rolls down an inclined plane.The ratio of rotational kinetic energy
- An electron in the hydrogen atom jumps from excited state n to the ground state
- If a body is rolling on the surface, its total energy will be
- A car moving with a speed of 50 kmh⁻¹ can be stopped by brakes after at least 6 m
- How much work is required to carry a 6 μC charge from the negative terminal
Topics: Work Energy and Power
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A circular disc rolls down an inclined plane.The ratio of rotational kinetic energy
- An electron in the hydrogen atom jumps from excited state n to the ground state
- If a body is rolling on the surface, its total energy will be
- A car moving with a speed of 50 kmh⁻¹ can be stopped by brakes after at least 6 m
- How much work is required to carry a 6 μC charge from the negative terminal
Topics: Work Energy and Power (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply