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In vacuum, to travel distance d, light takes time t and in medium to travel distance 5d, it takes time T. The critical angle of the medium is
Options
(a) sin⁻¹(5T/t)
(b) sin⁻¹(5t/3T)
(c) sin⁻¹(5t/T)
(d) sin⁻¹(3t/5T)
Correct Answer:
sin⁻¹(5t/T)
Explanation:
In vacuum, c = d / t
In medium, v = 5d / T
As refractive index , μ = c / v = (d/t) / (5d/T) = T / 5t
Also, sin C = 1 / μ [If C is critical angle]
Therefore, C = sin⁻¹ [5t / T]
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Topics: Ray Optics
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- At what temperature will the rms speed of air molecules be double that of NTP?
- An electric bulb has a rated power of 50W at 100 V. if it used on an a.c. source
- If the cold junction of a thermo-couple is kept at 0⁰C and the hot junction is kept
- If a magnetic substance is brought near the north or the south pole of a bar magnet
- For the normal eye, the cornea of eye provides a converging power of 40D
Topics: Ray Optics (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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