| ⇦ | 
| ⇨ |
A conveyor belt is moving at a constant speed of 2 m/s. A box is gently dropped on it. The coefficient of friction between them is µ = 0.5. The distance that the box will move relative to belt before coming to rest on it taking g = 10 ms⁻², is
Options
(a) 1.2 m
(b) 0.6 m
(c) zero
(d) 0.4 m
Correct Answer:
0.4 m
Explanation:
Frictional force oon the box f = µmg
Acceleration in the box a = µg = 5 ms⁻²
v² = u² + 2as
⇒ 0 = 2² + 2 x (5)s
⇒ s = – 2/5 w.r.t. belt
⇒ distance = 0.4 m
Related Questions: - Which of the following physical quantities has neither dimensions nor unit
- When a p-n junction is reverse biased, then the current through the junction
- In depletion layer of unbiased P-N junction
- Which of the following quantities has units but not dimensions
- If the earth shrink such that its mass does not change but radius decreases to one
Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which of the following physical quantities has neither dimensions nor unit
- When a p-n junction is reverse biased, then the current through the junction
- In depletion layer of unbiased P-N junction
- Which of the following quantities has units but not dimensions
- If the earth shrink such that its mass does not change but radius decreases to one
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply