| ⇦ |
| ⇨ |
A conducting square frame of side ‘a’ and a long straight wire carrying current I are located in the same plane as shown in the figure. The frame moves to the right with a constant velocity ‘V’. The emf induced in the frame will be proportional to

Options
(a) 1/(2x-a)²
(b) 1/(2x+a)²
(c) 1/(2x-a)(2x+a)
(d) 1/x²
Correct Answer:
1/(2x-a)(2x+a)
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - If fundamental frequency of closed pipe is 50 Hz then frequency of 2nd overtone
- Two spheres of mass m and M are situated in air and the gravitational force
- Radius of a soap bubble is increased from R to 2R. Work done in this process
- Two wheels having radii in the ratio 1:3 are connected by a common belt
- Four cells, each of emf E and internal resistance r, are connected in series across
Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If fundamental frequency of closed pipe is 50 Hz then frequency of 2nd overtone
- Two spheres of mass m and M are situated in air and the gravitational force
- Radius of a soap bubble is increased from R to 2R. Work done in this process
- Two wheels having radii in the ratio 1:3 are connected by a common belt
- Four cells, each of emf E and internal resistance r, are connected in series across
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply