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A common emitter amplifier is designed with n-p-n transistor (α=0.99). The input impedence is 1kΩ and load is 10kΩ. The voltage gain will be
Options
(a) 9900
(b) 99
(c) 9.9
(d) 990
Correct Answer:
990
Explanation:
Voltage gain = β × Resistance gain
β = α/(1-α) = 0.99 / (1-0.99) = 99
Resistance gain = (10 × 10³) = 10
Voltage gain = 99 × 10 = 990
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Topics: Electronic Devices
(124)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The magnifying power of a telescope is 9. When it is adjusted for parallel rays
- Wave nature of light is verified by
- A generator at a utility company produces 100 A of current at 4000 V. The voltage
- The emission line of Lyman corresponds to the absorption line in laboratory temperature
- A particle of mass m is driven by a machine that delivers a constant power k watts
Topics: Electronic Devices (124)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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