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A common emitter amplifier is designed with n-p-n transistor (α=0.99). The input impedence is 1kΩ and load is 10kΩ. The voltage gain will be
Options
(a) 9900
(b) 99
(c) 9.9
(d) 990
Correct Answer:
990
Explanation:
Voltage gain = β × Resistance gain
β = α/(1-α) = 0.99 / (1-0.99) = 99
Resistance gain = (10 × 10³) = 10
Voltage gain = 99 × 10 = 990
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Topics: Electronic Devices
(124)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The internal energy change in a system that has absorbed 2 kcals of heat
- Two bodies of mass 10 kg and 5 kg moving in concentric orbits of radius
- If a vector 2i+3j+8k is perpendicular to the vector 4j-4i+αk, then value of α is
- Which one of the following statement is FALSE ?
- A coil of 40 henry inductance is connected in series with a resistance of 8 ohm
Topics: Electronic Devices (124)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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