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A common emitter amplifier is designed with n-p-n transistor (α=0.99). The input impedence is 1kΩ and load is 10kΩ. The voltage gain will be
Options
(a) 9900
(b) 99
(c) 9.9
(d) 990
Correct Answer:
990
Explanation:
Voltage gain = β × Resistance gain
β = α/(1-α) = 0.99 / (1-0.99) = 99
Resistance gain = (10 × 10³) = 10
Voltage gain = 99 × 10 = 990
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Topics: Electronic Devices
(124)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In Young’s double slit experiment, the fringe width is 1×10⁻⁴ m, if the distance
- The e.m.f. of a battery is 2 V and its internal resistance is 0.5 Ω. The maximum
- A solenoid of length l metre has self inductance L henry. If number of turns
- An electric dipole placed in a non-uniform electric field experiences
- A uniform rope of length 12 m and mass 6 kg hangs vertically from a rigid support.
Topics: Electronic Devices (124)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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