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A common emitter amplifier is designed with n-p-n transistor (α=0.99). The input impedence is 1kΩ and load is 10kΩ. The voltage gain will be
Options
(a) 9900
(b) 99
(c) 9.9
(d) 990
Correct Answer:
990
Explanation:
Voltage gain = β × Resistance gain
β = α/(1-α) = 0.99 / (1-0.99) = 99
Resistance gain = (10 × 10³) = 10
Voltage gain = 99 × 10 = 990
Related Questions: - The ionisation energy of an electron in the ground state of helium atom is 24.6 eV.
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Topics: Electronic Devices
(124)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The ionisation energy of an electron in the ground state of helium atom is 24.6 eV.
- The maximum velocity of a particle, executing simple harmonic motion with an amplitude
- The primary and secondary coil of the transformer have 50 and 1500 turns respectively
- Sound waves travel at 350m/s through a warm air and at 3500 m/s through brass
- A fringe width of a certain interference pattern is β=0.002 cm. What is the distance
Topics: Electronic Devices (124)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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