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A common emitter amplifier is designed with n-p-n transistor (α=0.99). The input impedence is 1kΩ and load is 10kΩ. The voltage gain will be
Options
(a) 9900
(b) 99
(c) 9.9
(d) 990
Correct Answer:
990
Explanation:
Voltage gain = β × Resistance gain
β = α/(1-α) = 0.99 / (1-0.99) = 99
Resistance gain = (10 × 10³) = 10
Voltage gain = 99 × 10 = 990
Related Questions: - A transistor-oscillator using a resonant circuit with an inductor L
- Two coils have the mutual inductance of 0.05 H.
- One way in which the operation of a n-p-n transistor differs from that of a p-n-p
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Topics: Electronic Devices
(124)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A transistor-oscillator using a resonant circuit with an inductor L
- Two coils have the mutual inductance of 0.05 H.
- One way in which the operation of a n-p-n transistor differs from that of a p-n-p
- A car is moving in a circular horizontal track of radius 10.0 m with a constant speed
- A parallel plate capacitor as a uniform electric field E in the space between the plates
Topics: Electronic Devices (124)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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