| ⇦ | 
| ⇨ |
A common emitter amplifier has a voltage gain of 50, an input impedance of 100Ω and an output impedance of 200Ω. The power gain of the amplifier is
Options
(a) 500
(b) 1000
(c) 1250
(d) 50
Correct Answer:
1250
Explanation:
Power gain = voltage gain x current gain
= Vₕ . Iₕ = V₀ / Vᵢ . I₀ / Iᵢ
= V₀² / Vᵢ² . Rᵢ / R₀ = 50 x 50 x 100/200
= 2500 / 2 = 1250
Related Questions: - The order of the electric field near the earth’s surface is
- Two coils of self inductance 2 mH and 8 mH are placed so close together
- A parallel plate condenser with a dielectric of dielectric constant K between the plates
- If white light is used in Young’s double slit experiment
- An electric lamp is connected to 220 V, 50 Hz supply. Then the peak voltge is
Topics: Electronic Devices
(124)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The order of the electric field near the earth’s surface is
- Two coils of self inductance 2 mH and 8 mH are placed so close together
- A parallel plate condenser with a dielectric of dielectric constant K between the plates
- If white light is used in Young’s double slit experiment
- An electric lamp is connected to 220 V, 50 Hz supply. Then the peak voltge is
Topics: Electronic Devices (124)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply