| ⇦ | 
| ⇨ |
A charge Q is uniformly distributed over a large plastic plate. The electric field at point P close to centre of plate is 10Vm⁻¹. If the plastic plate is replaced by copper plate of the same geometrical dimension and carrying the same charge Q, then the electric field at that point will be
Options
(a) zero
(b) 5Vm⁻¹
(c) 10Vm⁻¹
(d) 20Vm⁻¹
Correct Answer:
10Vm⁻¹
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A particle is moving such that its position coordinates (x,y) are (2 m,3 m) at time
- Stress to strain ratio is equivalent to
- A copper disc of radius 0.1 m is rotated about its centre, with 10 revolutions
- A particle of mass 100g tied to a string is rotated along a circle of radius 0.5 m
- Two beams of light having intensities I and 4I interfere to produce a fringe pattern
Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A particle is moving such that its position coordinates (x,y) are (2 m,3 m) at time
- Stress to strain ratio is equivalent to
- A copper disc of radius 0.1 m is rotated about its centre, with 10 revolutions
- A particle of mass 100g tied to a string is rotated along a circle of radius 0.5 m
- Two beams of light having intensities I and 4I interfere to produce a fringe pattern
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Electric field will remain same as charge density σ remain same (E=σ/ε0).