| ⇦ | 
| ⇨ |
A certain mass of Hydrogen is changed to Helium by the process of fusion. The mass defect in fusion reaction is 0.02866 a.m.u. The energy liberated per a.m.u. is (Given : 1 a.m.u. = 931 MeV)
Options
(a) 26.7 MeV
(b) 6.675 MeV
(c) 13.35 MeV
(d) 2.67 MeV
Correct Answer:
6.675 MeV
Explanation:
Mass defect m = 0.02866 a.m.u.
Energy = 0.02866 x 931 = 26.7 MeV
As ₁H² + ₁H² → ₂He⁴
Energy liberated per a.m.u. = 13.35/2 MeV = 6.675 MeV
Related Questions: - When the temperature increases, the viscocity of
- A solid sphere, disc and solid cylinder all of the same mass and made up of same material
- A body, which emits radiations of all possible wavelengths, is known as
- A super conductor exhibits perfect
- The half life of a radioactive isotope ‘X’ is 20 years. It decays to another element Y
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- When the temperature increases, the viscocity of
- A solid sphere, disc and solid cylinder all of the same mass and made up of same material
- A body, which emits radiations of all possible wavelengths, is known as
- A super conductor exhibits perfect
- The half life of a radioactive isotope ‘X’ is 20 years. It decays to another element Y
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply