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A certain mass of Hydrogen is changed to Helium by the process of fusion. The mass defect in fusion reaction is 0.02866 a.m.u. The energy liberated per a.m.u. is (Given : 1 a.m.u. = 931 MeV)
Options
(a) 26.7 MeV
(b) 6.675 MeV
(c) 13.35 MeV
(d) 2.67 MeV
Correct Answer:
6.675 MeV
Explanation:
Mass defect m = 0.02866 a.m.u.
Energy = 0.02866 x 931 = 26.7 MeV
As ₁H² + ₁H² → ₂He⁴
Energy liberated per a.m.u. = 13.35/2 MeV = 6.675 MeV
Related Questions: - A particle is under two mutually perpendicular simple harmonic motions
- If sink is at a temperature of -39⁰C and source at 0⁰C, then efficiency will be
- The atomic number of the most common element in nuclear fusion is
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Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A particle is under two mutually perpendicular simple harmonic motions
- If sink is at a temperature of -39⁰C and source at 0⁰C, then efficiency will be
- The atomic number of the most common element in nuclear fusion is
- Moderator used in nuclear reactor is
- A galvanometer coil has a resistance of 15 ohm and gives full scale deflection
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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