| ⇦ | 
| ⇨ |
A certain mass of Hydrogen is changed to Helium by the process of fusion. The mass defect in fusion reaction is 0.02866 a.m.u. The energy liberated per a.m.u. is (Given : 1 a.m.u. = 931 MeV)
Options
(a) 26.7 MeV
(b) 6.675 MeV
(c) 13.35 MeV
(d) 2.67 MeV
Correct Answer:
6.675 MeV
Explanation:
Mass defect m = 0.02866 a.m.u.
Energy = 0.02866 x 931 = 26.7 MeV
As ₁H² + ₁H² → ₂He⁴
Energy liberated per a.m.u. = 13.35/2 MeV = 6.675 MeV
Related Questions: - A pure semiconductor behaves slightly as a conductor at
- If h is planck’s constant and λ is wavelength, h/λ has dimensions of
- What is the energy of photon whose wavelength is 6840 Å?
- A block of mass 10 kg is moving in X-direction with a constant speed of 10 ms⁻¹
- A beam of cathode rays is subjected to crossed Electric (E) and Magnetic fields (B)
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A pure semiconductor behaves slightly as a conductor at
- If h is planck’s constant and λ is wavelength, h/λ has dimensions of
- What is the energy of photon whose wavelength is 6840 Å?
- A block of mass 10 kg is moving in X-direction with a constant speed of 10 ms⁻¹
- A beam of cathode rays is subjected to crossed Electric (E) and Magnetic fields (B)
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply