| ⇦ | 
| ⇨ |
A certain current on passing through a galvanometer produces a deflection of 100 divisions. When a shunt of one ohm is connected, the deflection reduces to division. The galvanometer resistance is
Options
(a) 10 Ω
(b) 9.9 Ω
(c) 100 Ω
(d) 99 Ω
Correct Answer:
99 Ω
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions:
- Water drops fall from a top on the floor 5 m below at regular intervals
- In semiconductor at a room temperature
- A light whose frequency is equal to 6.0 x 10¹⁴ Hz is incident on a metal
- A block of mass 0.50 kg is moving with a speed of 2.00 ms⁻¹ on a smooth surface.
- A road of width 20 m forms an arc of radius 15 m,its outer edge is 2m higher than
Topics: Current Electricity
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Explanation: Is=I-Ig=100-1=99
G = Is*S/Ig = (99*1)/1 = 99 ohm