A body takes 5 minute for cooling from 50⁰C to 40⁰C. Its temperature

⇦

⇨

A body takes 5 minute for cooling from 50⁰C to 40⁰C. Its temperature comes down to 33.33⁰C in next 5 minute. Temperature of surroundings is

Options

(a) 15⁰C
(b) 20⁰C
(c) 25⁰C
(d) 10⁰C

Correct Answer:

20⁰C

Explanation:

Apply Newton’s law of cooling
In first case, (50 – 40)/5 = K [(50+40)/2 – θ]
⇒ 2 = K [45 – θ] ——(i)
In second case, take 33.33 = 33 x (1/3) = 100/3
[40 – (100/3)]/5 = K {[40 + (100/3)/2] – θ}
⇒ 20/(5×3) = K [(110/3) – θ] ——(ii)
(i)/(ii) = (2 x 5 x 3)/20 = (45 – θ) / [(110/3) – θ]
⇒ 3/2 = (45 – θ) / [(110/3) – θ]
= 110 – 30 = 90 – 20 ⇒ θ = 20⁰C.

Related Questions:

1. Electric potential at any point is V= -5x +3y + √(15) z. Then the magnitude of electric
2. A particle is executing SHM along a straight line. Its velocities at distances
3. The force F acting on a particle of mass m is indicated by the force-time graph
4. The decay constant of a radio isotope is λ. If A₁ and A₂ are its activities at time
5. Four indentical thin rods each of mass M and length l, form a square frame

Topics: Properties of Bulk Matter (130)
Subject: Physics (2479)

---

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

---

Share this page with your friends