| ⇦ |
| ⇨ |
A body takes 5 minute for cooling from 50⁰C to 40⁰C. Its temperature comes down to 33.33⁰C in next 5 minute. Temperature of surroundings is
Options
(a) 15⁰C
(b) 20⁰C
(c) 25⁰C
(d) 10⁰C
Correct Answer:
20⁰C
Explanation:
Apply Newton’s law of cooling
In first case, (50 – 40)/5 = K [(50+40)/2 – θ]
⇒ 2 = K [45 – θ] ——(i)
In second case, take 33.33 = 33 x (1/3) = 100/3
[40 – (100/3)]/5 = K {[40 + (100/3)/2] – θ}
⇒ 20/(5×3) = K [(110/3) – θ] ——(ii)
(i)/(ii) = (2 x 5 x 3)/20 = (45 – θ) / [(110/3) – θ]
⇒ 3/2 = (45 – θ) / [(110/3) – θ]
= 110 – 30 = 90 – 20 ⇒ θ = 20⁰C.
Related Questions: - At what distance from the centre of earth, the value of acceleration due to gravity
- A particle of mass m is driven by a machine that delivers a constant power k watts
- A simple pendulum performs simple harmonic motion about x = 0 with an amplitude
- A thin equiconvex lens of refractive index 3/2 and radius of curvature 30 cm
- The velocity of a particle at an instant is 10 ms⁻¹ and after 5 s the velocity
Topics: Properties of Bulk Matter
(130)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- At what distance from the centre of earth, the value of acceleration due to gravity
- A particle of mass m is driven by a machine that delivers a constant power k watts
- A simple pendulum performs simple harmonic motion about x = 0 with an amplitude
- A thin equiconvex lens of refractive index 3/2 and radius of curvature 30 cm
- The velocity of a particle at an instant is 10 ms⁻¹ and after 5 s the velocity
Topics: Properties of Bulk Matter (130)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply