| ⇦ |
| ⇨ |
A body takes 5 minute for cooling from 50⁰C to 40⁰C. Its temperature comes down to 33.33⁰C in next 5 minute. Temperature of surroundings is
Options
(a) 15⁰C
(b) 20⁰C
(c) 25⁰C
(d) 10⁰C
Correct Answer:
20⁰C
Explanation:
Apply Newton’s law of cooling
In first case, (50 – 40)/5 = K [(50+40)/2 – θ]
⇒ 2 = K [45 – θ] ——(i)
In second case, take 33.33 = 33 x (1/3) = 100/3
[40 – (100/3)]/5 = K {[40 + (100/3)/2] – θ}
⇒ 20/(5×3) = K [(110/3) – θ] ——(ii)
(i)/(ii) = (2 x 5 x 3)/20 = (45 – θ) / [(110/3) – θ]
⇒ 3/2 = (45 – θ) / [(110/3) – θ]
= 110 – 30 = 90 – 20 ⇒ θ = 20⁰C.
Related Questions: - When a p-n junction is reverse biased, then the current through the junction
- Two point objects of masses 1.5 g and 2.5 g respectively are at a distance of 16 cm
- For the radioactive nuclei that undergo either α or β decay, which one
- If A=4i+4j+4k and b=3i+j+4k, then angle between vectors A and B is
- The displacement of a particle along the x-axis is given by x = a sin² ?t
Topics: Properties of Bulk Matter
(130)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- When a p-n junction is reverse biased, then the current through the junction
- Two point objects of masses 1.5 g and 2.5 g respectively are at a distance of 16 cm
- For the radioactive nuclei that undergo either α or β decay, which one
- If A=4i+4j+4k and b=3i+j+4k, then angle between vectors A and B is
- The displacement of a particle along the x-axis is given by x = a sin² ?t
Topics: Properties of Bulk Matter (130)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply