| ⇦ |
| ⇨ |
Two spherical nuclei have mass numbers 216 and 64 with their radii R₁ and R₂, respectively. The ratio, R₁/R₂ is equal to
Options
(a) (3:2)
(b) (1:3)
(c) (1:2)
(d) (2:3)
Correct Answer:
(3:2)
Explanation:
Radius of nuclei having mass number A is determined as
R = R₀ A¹/³ (where R₀ = constant)
where, R₀ = 1.2 x 10⁻¹⁵ m
This implies, R₁/R₂ = (A₁/A₂)¹/³ = (216/64)¹/³ = 6/4
R₁:R₂ = 3:2
Related Questions: - If the radioactive dacay constant of radium is 1.07 x 10⁻⁴ year⁻¹, then its half-life
- All components of the electromagnetic spectrum in vacuum have the same
- A beam of cathode rays is subjected to crossed Electric (E) and Magnetic fields (B)
- Two circuits have a mutual inductance of 0.1 H. What average e.m.f. is induced
- A ball is dropped into a well in which the water level is at a depth h below the top
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If the radioactive dacay constant of radium is 1.07 x 10⁻⁴ year⁻¹, then its half-life
- All components of the electromagnetic spectrum in vacuum have the same
- A beam of cathode rays is subjected to crossed Electric (E) and Magnetic fields (B)
- Two circuits have a mutual inductance of 0.1 H. What average e.m.f. is induced
- A ball is dropped into a well in which the water level is at a depth h below the top
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

R=R°A^1/3. (R°=constant
R1÷R2 =(A1÷A2)^1/3
=(216÷64)^1/3
=6÷4.
=> R1:R2 = 3:2