| ⇦ | 
| ⇨ |
A bar magnet is hung by a thin cotton thread in a uniform horizontal magnetic field and is in equillibrium state. The energy required to rotate it by 60⁰ is W. Now the torque required to keep the magnet in this new position is
Options
(a) W/√3
(b) √3W
(c) √3W/2
(d) 2W/√3
Correct Answer:
√3W
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - An alternating electric field, of frequency v, is applied across the dees (radius = R)
- The ratio of the acceleration for a solid sphere(mass m and radius R)rolling down
- The ionisation energy of an electron in the ground state of helium atom is 24.6 eV.
- When alpha particles captures and electron, then it becomes a
- Which logic gate is represented by the following combination of logic gate?
Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An alternating electric field, of frequency v, is applied across the dees (radius = R)
- The ratio of the acceleration for a solid sphere(mass m and radius R)rolling down
- The ionisation energy of an electron in the ground state of helium atom is 24.6 eV.
- When alpha particles captures and electron, then it becomes a
- Which logic gate is represented by the following combination of logic gate?
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply