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A bar magnet is hung by a thin cotton thread in a uniform horizontal magnetic field and is in equillibrium state. The energy required to rotate it by 60⁰ is W. Now the torque required to keep the magnet in this new position is
Options
(a) W/√3
(b) √3W
(c) √3W/2
(d) 2W/√3
Correct Answer:
√3W
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A parallel plate capacitor with air between the plates has a capacitance of 9 pF.
- For inelastic collision between two spherical rigid bodies
- The moment of inertia of a semicircular ring about the centre is
- The current in a self-inductance L=40 mH is to be increased uniformly from 1A to 11 A
- The second overtone of an open pipe is in resonance with the first overtone
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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