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A bar magnet is hung by a thin cotton thread in a uniform horizontal magnetic field and is in equillibrium state. The energy required to rotate it by 60⁰ is W. Now the torque required to keep the magnet in this new position is
Options
(a) W/√3
(b) √3W
(c) √3W/2
(d) 2W/√3
Correct Answer:
√3W
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The current in the coil of inductance 5H decreases at the rate of 2 A/s
- In the series resonance the value of impedence is 3 Ω and the resistance is 4Ω,
- If the velocity of sound in air is 350 m/s, thent he fundamental frequency
- A missile is fired for maximum range with an initial velocity of 20 m/s
- The escape velocity from the earth’s surface is 11 kms⁻¹.A certain planet
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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