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A bar magnet is hung by a thin cotton thread in a uniform horizontal magnetic field and is in equillibrium state. The energy required to rotate it by 60⁰ is W. Now the torque required to keep the magnet in this new position is
Options
(a) W/√3
(b) √3W
(c) √3W/2
(d) 2W/√3
Correct Answer:
√3W
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A fringe width of a certain interference pattern is β=0.002 cm. What is the distance
- Two radiations of photons energies 1 eV and 2.5 eV, successively
- Two charges placed in air repel each other by a force of 10⁻⁴ N. When oil is
- A thermocouple of negligible resistance produces an e.m.f. of 40 µV/⁰C in the linear range
- An isolated sphere has a capacitance of 50pF. What would be the radius of the sphere?
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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