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A bar magnet is hung by a thin cotton thread in a uniform horizontal magnetic field and is in equillibrium state. The energy required to rotate it by 60⁰ is W. Now the torque required to keep the magnet in this new position is
Options
(a) W/√3
(b) √3W
(c) √3W/2
(d) 2W/√3
Correct Answer:
√3W
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Three capacitors of capacitances 3 μF, 10 μF and 15 μF are connected in series
- A body is thrown with a velocity of 9.8 m/s making angle of 30° with the horizontal
- In intrinsic semiconductor at room temperature number of electrons and holes are
- The oscillation of a body on a smooth horizontal surface is represented by the equation
- A body of mass 120 kg and density 600 kg/m³ floats in water.
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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