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A bar magnet is hung by a thin cotton thread in a uniform horizontal magnetic field and is in equillibrium state. The energy required to rotate it by 60⁰ is W. Now the torque required to keep the magnet in this new position is
Options
(a) W/√3
(b) √3W
(c) √3W/2
(d) 2W/√3
Correct Answer:
√3W
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- SI unit of magnetic dipole moment is
- Diameter of the objective of a telescope is 200 cm. What is the resolving power
- An automobile engine develops 100 kW when rotating at a speed of 1800 rev/min
- A body of mass 2 kg is moved by a force F=3x where x is the distance covered.
- A very small circular loop of radius a is initially (at t=0) coplanar and concentric
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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