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A person of mass 60 kg is inside a lift of mass 940 kg and presses the button on control panel.The lift starts moving upwards with an acceleration 1.0 m/s². If g = 10 ms⁻², the tension in the supporting cable is
Options
(a) 8600 N
(b) 9680 N
(c) 11000 N
(d) 1200 N
Correct Answer:
11000 N
Explanation:
Total Mass = (60 + 940) kg = 1000 kg
Let T be the tension in the supporting cable, then,
T =M (g+a)
⇒ T = 1000(10+1) =11000 N
Related Questions: - An object placed at 20 cm in front of a concave mirror produces three times
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Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An object placed at 20 cm in front of a concave mirror produces three times
- Two concentric coils each of radius equal to 2π cm are placed at right angles
- One coolie takes 1 minute to raise a suitcase through a height of 2 m
- If rope of lift breaks suddenly, the tension exerted by the surface of the lift
- A particle has initial velocity (3i + 4j) and acceleration (0.1 i+0.3j). It’s speed after 10s
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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